Question

if 2^2x-1 + 2^1-2x = 2 then 'x' =____
A) 0.5
B) -0.5
C) 1
D) 0​

Answer 1

Answer:

C,coc playing aaa....????????

Answer 2

Answer:

0

Step-by-step explanation:

by substituting each value in given equation we will check which value of X will satisfy the given equation.

putting X=0.5 in given equation we get

LHS=2^2(0.5)-1+1-2(0.5)=2-1+1-1=1 which is not equal to RHS

so 0.5 is not X value

then substituting X=(-0.5)

LHS=2^2(-0.5)-1+2-2(-0.5)

=2^(-1)-1+2+1

= (1/2)-1+2+1

=5/2 not equal to RHS

so X is not -0.5

now substituting X=1

LHS=2^2(1)-1+2-2(1)=4-1+2-2=3 not equal to RHS

so X is not equal to 1

then substituting X=0 we get

LHS=2^2(0)-1+2-2(0)=1-1+2-0=2 =RHS

therefore X=0 satisfies the given equation so the value of X is zero