Question

If 2^(2x-1) = 8^(3-x) then the value of x is

Answer 1

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Answer 2

Answer:

Here we will find the value of $x$ using the given equation. The value of $x=2$.

Step-by-step explanation:

Now consider the left side and right side of the equation.

That is,     $2^{(2x-1)}=8^{(3-x)}$

On the right side, $8$ can be written as $2^{3}$.

So apply this $2^{3}$ to the given equation.

               $2^{(2x-1)} =2^{3(3-x)}$

Now the multiply $3$ and $3-x$ on the right side. It should be written as,

              $2^{(2x-1)} =2^{(9-3x)}$

Here base are the same at left side and right side. So we can equal the power.

That is,   $2x-1=9-3x$

Now arrange the $x$ terms and constants. That is, $-3x$ on the right side should comes to left side. So it will change into $3x$.

Similarly, $-1$ on the left side should come to right side. So it will change into $1$.

That is,  $2x+3x= 9+1$

Now add $2x$ and $3x$ on the left side. Add $9$ and $1$.

                    $5x=10$

                      $x=\frac{10}{5}$

                      $x=2$