Question

if 2^2x+3-3^2.2^x+1=0 then value of x is​

Answer 1

Answer: 2^(2x+3)-3^2.2^x+1=0

or, (2^2x)×(2^3)-9.2^x+1=0

or , 8×2^2x-9×2^x+1=0

or, 8×(2^x)^2–9×2^x+1=0

or, 8m^2–9m+1=0 ,asuming 2^x=m

or, 8m^2–8m-m+1=0

or, 8m(m-1)-1(m-1)=0

or, ( m-1)(8m-1)=0

or, m=1 or 1/8

when m=1 , 2^x=1=2^0 , x=0

when m=1/8, 2^x=1/8=1/2^3=2^(-3)

x= (-3)

x=0 or -3

hope it helps!!!!!!!!