Math, asked by qwert81, 8 months ago

if 2^2x+3-3^2*2^x+1=0 ,x=?

Answers

Answered by sohalsukhdeep23
3

Answer:

x=0 or -3

Step-by-step explanation:

2^(2x+3)-3^2.2^x+1=0

(2^2x)×(2^3)-9.2^x+1=0

=8×2^2x-9×2^x+1=0

=8×(2^x)^2–9×2^x+1=0

=8m^2–9m+1=0 ,asuming 2^x=m

=8m^2–8m-m+1=0

=8m(m-1)-1(m-1)=0

=( m-1)(8m-1)=0

=m=1 or 1/8

when m=1 , 2^x=1=2^0 , x=0

when m=1/8, 2^x=1/8=1/2^3=2^(-3)

x= (-3)

x=0 or -3 ans

plz mark brainliest.

Answered by zunashakhan7
0

Answer:

this is the question of math I am student of physics

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