If 2(2x - y) = 16 and 2(x + y) = 32, the value of (xy/2) is
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2(2x-y)=16
2x-y= 8 eq1)
2(x+y)=32
(x+y)= 16 eq 2)
Solving both eqn
x= 8 y=8
So xy/2= 64/2=32 Ans
2x-y= 8 eq1)
2(x+y)=32
(x+y)= 16 eq 2)
Solving both eqn
x= 8 y=8
So xy/2= 64/2=32 Ans
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