Math, asked by kshitijpanday06, 2 months ago

If 2^(2x-y)=16 and 2^(x+y)=32,then value of xy is​

Answers

Answered by Anonymous
1

Step-by-step explanation:

2^(2x-y)=16 => 2^(2x-y) = 2⁴ => 2x - y = 4

2^(x+y)=32 => 2^(x+y) = 2⁵ => x + y = 5

2x - y = 4

x + y = 5

________

3x = 9

x = 3

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