Question

if 2^2x-y=32,2^x+y=16,findx^2+y^2

Answer 1

Answer:

x= 3 , y = 1.

x^2+y^2 = 10

Step-by-step explanation:

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Answer 2

${2}^{2x - y} = 32 \\ {2}^{2x - y} = {2}^{5} \\ 2x - y = 5..........(1)$

Now,

${2}^{x + y} = 16 \\ {2}^{x + y} = {2}^{4} \\ x + y = 4..........(2)$

On solving equation (1) and (2)

we get,x=3 and y=1