If 2^2x - y = 32 and 2^x+y = 16 then x2 + y2
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Answer:
x² + y² = 10
Step-by-step explanation:
2^(2x - y) = 32
2^(2x - y) = 2^5
Equating exponents
2x - y = 5 --------> (1)
2^(x + y) = 16
2^(x + y) = 2^4
Equating exponents
x + y = 4 --------> (2)
Adding equations 1 and 2
2x - y + x + y = 5 + 4
3x = 9
x = 3
y = 1
x² + y² = 3² + 1²
= 9 + 1
x² + y² = 10
Hope this helps! :)
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