Math, asked by Kassvi, 11 months ago

If 2^2x - y = 32 and 2^x+y = 16 then x2 + y2​

Answers

Answered by AccioNerd
33

Answer:

x² + y² = 10

Step-by-step explanation:

2^(2x - y) = 32

2^(2x - y) = 2^5

Equating exponents

2x - y = 5             --------> (1)

2^(x + y) = 16

2^(x + y) = 2^4

Equating exponents

x + y = 4              --------> (2)

Adding equations 1 and 2

2x - y + x + y = 5 + 4

3x = 9

x = 3

y = 1

x² + y² = 3² + 1²

           = 9 + 1

x² + y² = 10

Hope this helps! :)

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