Question

if 2^2x-y=32 and 2^x+y=16 then x²+y²​

Answer 1

Step-by-step explanation:

2^2x-y ==32

then2^2x-y=2^5

,2x-y=5----------1

similarly,x+y=4------------2

by solving eqn 1 and 2 we get;

x=3a and y=1

so x^2+y^2=3^2+1^2

=9+1

=10

Answer 2

Step-by-step explanation:

(2)2x+y=32

x=4-32

x=28

y=x-16

y=28-16

y=12

(28)^2 + (12)^2

784+144

=928