if (2.3)× = (0.23)y =1000 then find the value of 1/x-1/y
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(2.3)^x=1000 and (0.23)^y=1000
log(2.3)^x =log1000 and log(0.23)^y=1000
xlog(2.3)=log10^3 and log(0.23)^y =log10^3
xlog(2.3) = 3log10 and ylog(0.23) =3log10
xlog(2.3) = 3×1 and ylog(0.23)=3 [log10=1]
⇒log(2.3)=3/x and log0.23 =3/y
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3/x -3/y =log2.3 -log(0.23)
3(1/x - 1/y) =log(2.3/0.23)
⇒1/x - 1/y ={log(10)}/3
⇒1/x-1/y =(1)/3
⇒1/x -1/y =1/3
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