If √2+√3/√18-√12=a-b√6 find the value of a and b
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if I rout 2+i rout3/i rout 18-i rout 12=a-bi rout 6
dived the some 2
2+3/18-12=(a²-b²)6
5/6=(a²-b²)6
5=a²-b²
a²=5b²
b²=5a²
dived the some 2
2+3/18-12=(a²-b²)6
5/6=(a²-b²)6
5=a²-b²
a²=5b²
b²=5a²
Anonymous:
hai this is ur answer
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