if 2+√3/2-√3 + 2-√3/2+√3 + √3-1/√3+1 = a+b√3 ,then a+4b =
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2+√3/2-√3=a+b√3
=(2+√3)*(2+√3)/(2-√3)*(2+√3)=a+b√3
=(4+3+4√3)/(4-3)=a+b√3
=7+4√3=a+b√3
(comparing both the sides ,we get)
a= 7
b=4
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