If 2+√3/2-√3 is eqzal to a-√3 find a and b
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Answered by
1
Answer:
Given: r1 = 1 cm, r2 = 2.5 cm, h =(7-1)= 6 cm
l = √(h² + (r2-r1)²)
= √((6)² + (2.5-1)²) cm
= √(36 + 2.25 )cm
= √38.25 cm
= 6.18cm
So,
External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)
= (22/7)(r1+r2)l +(2)(22/7)(r1)
= (22/7) [(1+2.5)6.18 + 2×(1)²] cm²
= (22/7)(3.5 × 6.18 +2) cm²
= (22/7) (21.63+2) cm²
= (22/7) × 23.63 cm²
= 519.86/7 cm²
= 74.26 cm²
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Answered by
3
Answer:
a = 7 , b = 4
your answer is in the above attachment
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