Question

If 2,3 4,0 are the points that lies on equation px+qy=1 find value of p and q then plot the graph of equation so obtained.

Answer 1

Point (2, 3) lies on the line px + qy = 1

∴p×2 +q×3 = 1⇒2p +3q= 1          ...1

Again, point (4, 0) lies on the line px + qy = 1

∴p×4 +q×0= 1⇒4p = 1  => p= 1/4          ...2
Substituting the value of p in equation (1), we get:
   2p +3q= 1⇒2×1/4 +3q =1
1/2+3q=1=>1+6q=2=>6q=1=>q=1/6
∴ p = 1/4 and q = 1/6