If 2, 3, 4 be the eigen values of A, then A is
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Step-by-step explanation:
Suppose 'a' is an eigenvalue of A.
We know ,in linear algebra ,
Ax = ax , where ,a is an eigenvalue of A.
For power of A we have, A^(n)x = a^(n)x.
That means whatever be the power of A, the same will be the power of ,a,which is the eigenvalue of A.
Hence, A^(99)= 1^(99) =1 ,for eigenvalue 1.
A^(99)= 2^(99) for eigenvalue 2.
A^(99)=3^(99) for eigenvalue 3.
1^(99),2^(99),3^(99) are the eigenvalues of A^(99).
Hope this will help.
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