if 2/√3+√5 + 5 /√3-√5 = √3 + b√5,find the value of a and b
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Raghunath answered 4 year(s) ago
Surds
Solve the following:
i.If √3 - 1 / √3 + 1 = a+b√3
ii. If √2 + √3 / 3√2-2√3 = a-b√6
( find the value of a and b here)
Class-IX Maths
person
Asked by Sanika
Apr 24
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person
Raghunath , SubjectMatterExpert
Member since Apr 11 2014
Sol1) :
Given (√3 - 1) / (√3 + 1) ( rationalize numarator and denominator(√3 - 1) )
⇒ (√3 - 1)(√3 - 1) / (√3 + 1)(√3 - 1)
⇒ (√3 - 1)2 / (3 - 1)
⇒ (3 + 1-2√3 ) / 2
⇒ (2 -√3 ) = a+b√3 ⇒ a = 2 and b = -1
Sol2) :
Given (√2 + √3) / (3√2-2√3) ( rationalize numarator and denominator (3√2 + 2√3 ) )
⇒ (√2 + √3)(3√2 + 2√3 ) / (3√2-2√3)(3√2 + 2√3 )
⇒ (12 + 5√6) / (18-12)
⇒ (2 + (5√6) /6 ) = a-b√6
a = 2 and b = -5/6.
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Raghunath answered 4 year(s) ago
Surds
Solve the following:
i.If √3 - 1 / √3 + 1 = a+b√3
ii. If √2 + √3 / 3√2-2√3 = a-b√6
( find the value of a and b here)
Class-IX Maths
person
Asked by Sanika
Apr 24
1 Like
4551 views
editAnswer
Like Follow
1 Answers
Top Recommend
| Recent
person
Raghunath , SubjectMatterExpert
Member since Apr 11 2014
Sol1) :
Given (√3 - 1) / (√3 + 1) ( rationalize numarator and denominator(√3 - 1) )
⇒ (√3 - 1)(√3 - 1) / (√3 + 1)(√3 - 1)
⇒ (√3 - 1)2 / (3 - 1)
⇒ (3 + 1-2√3 ) / 2
⇒ (2 -√3 ) = a+b√3 ⇒ a = 2 and b = -1
Sol2) :
Given (√2 + √3) / (3√2-2√3) ( rationalize numarator and denominator (3√2 + 2√3 ) )
⇒ (√2 + √3)(3√2 + 2√3 ) / (3√2-2√3)(3√2 + 2√3 )
⇒ (12 + 5√6) / (18-12)
⇒ (2 + (5√6) /6 ) = a-b√6
a = 2 and b = -5/6.
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