If (2/√3 +√5) + (5/√3-√5) = a√3 +a√b find a and b
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hi flash ,
Given
(2/√3 +√5) + (5/√3-√5)
= (2(√3-√5) + 5(√3+√5) ) / (√3-√5 ) (√3-√5)
= (2√3 - 2√5 + 5√3 + 5√5) / 3-5
= 7√3 + 3√5 / -2
= (-7/2) √3 + (-3/2)√5
= a√3 + b√5
so
a = -7/2 = -3.5
b = -3/2 = -1.5
Hope it helped
Given
(2/√3 +√5) + (5/√3-√5)
= (2(√3-√5) + 5(√3+√5) ) / (√3-√5 ) (√3-√5)
= (2√3 - 2√5 + 5√3 + 5√5) / 3-5
= 7√3 + 3√5 / -2
= (-7/2) √3 + (-3/2)√5
= a√3 + b√5
so
a = -7/2 = -3.5
b = -3/2 = -1.5
Hope it helped
jish4you:
let me know if any doubts
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