If (2, 3, 5) is one end of a diameter of the sphere x^2 + y^2 + z^2 - 6x - 12y - 2z + 20 = 0,
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X=2,Y=3,Z=5
X2+y2+z2-6x-12y-2z+20=o
2^2+3^2+5^2-6 ✖ 2-12 ✖ 3-2 ✖ 5+20=0
Answer is 0
X2+y2+z2-6x-12y-2z+20=o
2^2+3^2+5^2-6 ✖ 2-12 ✖ 3-2 ✖ 5+20=0
Answer is 0
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