if 2+√3 and 2-√3 are two zeros of polynomial of x^3-6x^2+9x-2 then the other zero is
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Step-by-step explanation:
let the third root be k then equation will be (x-k)(x-2-√3)(x-2+√3)=0
now sum of the three roots is equal to -b/a i.e
k+ 2+√3+ 2-√3 = 6
from the given equation a=1, b= -6 , c=9 , d=-2
now,
k+4=6 => k=2
so the third root is 2
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