Question

If 2/3 and -3 are the zeros of the polynomial ax^ 2 + 7x + b then find the value of a and b

Answer 1

Answer:

a = 3,b = -2/3

Step-by-step explanation:

given polynomial ax^2+7x+b = 0

2/3,-3 are the zeros of the polynomial

(2/3)+(-3) = -7/a equation 1

(2/3)(-3) = b/a equation 2

from eq 1 ,

(2-9)/3 = -7/a

-7/3 = -7/a

-7 gets cancelled on both sides then,

1/3 = 1/a

a = 3

substitute a = 3 in eq 2

(2/3)(-3) = b/(3)

(2/-9) = b/(3)

-2/9 = b/3

b = (-2/9)×(3)

b = -2/3

Answer 2

Answer:

Hope this helps you ✌️✌️