Question

if 2/3 and -3 are the zeros of the quadratic equation ax²+7x+b then find a and b​

Answer 1

Answer:

The given equation is ax2 + 7x + b = 0. Its roots are given as x 1 = − 3 and x 2 = 2 3 . Thus, the values of a and b are 3 and −6, respectively.

Step-by-step explanation:

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Answer 2

Answer:

ax2+7x+b

Alpha + beta = 2/3-3 = 2-9/3 = -7/3

Also, Alpha + beta= -B/A = -7/a

comparing these 2 equations we get, a= 3

Now,

Alpha×Beta= 2/3× -3= -2

Also, Alpha×Beta= C/A = b/3

compiring these 2 equations,

b/3= -2

b= 3× -2

b = -6

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