Question

if 2/3 and -3 are zeros of quadratic polonomial ax^2+7x+b,then find the value of a and b​

Answer 1

Answer:

not sure check this question in digest(guide) of maths

Step-by-step explanation:

x=2/3 and x=3

put the value in equation:

a(2/3)^2 + 7(2/3) + b = 0

a(4/9) + 14/3) + b = 0

4a/9 + 14*3/3*3 +b = 0

4a/9+ 42/9 + b = 0

4a + 42 + 9b = 9

4a + 9b = - 33 ........1

put x = 3

a(3)^2 + 7(3) + b= 0

9a + 21 + b = 0

9a + b = -21. ... 2

Eliminate equations

we get

a= -39/19

b= -48/19