if 2, 3 are zero of polynomial
f(t) = 2 t² - 5t² +at + b find a b
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if there are two zeroes 2 & 3 then after putting their values in t we can find a and b.
when x=2
2t² - 5t + at + b
2 (2)² - 5(2) + 2a + b
8 - 10 + 2a + b
-2 + 2a + b
2a + b - 2..........(i)
and, when x =3
2t² - 5t + at + b
2 (3)² - 5(3) +3a + b
18 - 15 +3a + b
3a + b + 3...........(ii)
for eq (i) a= 2-b/2
now,putting a value in eq (ii) we get,
3 (2-b/2) + b +3=0
6 - 3b/2 + b +3=0
9 - 3b/2+b=0
9 - 5b/2=0
-5b = - 9 × 2
b = - 18/ - 5
b= 18/5
and a =2-b/2
a= 2-8/5/2
a = 1/5.
hence, b= 18/5
& a =1/5.
hope u got it...
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