If 2, 3 are zeros of polynomial x² + bx + 6 then b is equal to:
a. -5
b. -4
c. 6
d. 1
Answers
Answered by
1
Step-by-step explanation:
As the quadratic equation does no have two distinct real roots, so b2=4ac
b 2 =4a×6=24a
b 2 =24a
3a= 8b 2
3a+b= b 2/8 +b= 8b 2 +8b
= 8b(b+4) 2−16
Least value of (b+4)
2 =0
Hence least value of
8b/(b+4) 2 −16
=
8
0−16
=−2
Answered by
0
Answer:
a)-5
Step-by-step explanation:
As 2,3 are zeros of polynomial
(2)^2 + 2b +6 = 0
4 +2b + 6 = 0
10 + 2b = 0
2b = -10
b = -5
Hope this will help you
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