If (2 +√3) is a root of a quadratic equation x²+px+q=0 then find the value of P and q
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Step-by-step explanation:
other root is 2- root3 because these type of roots eexist in pairs
so 2 + root3 + 2 - root3 = -p
p= -4
(2 + root3 )( 2- root3) = q
q = 1
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