if √2/√3 is a solution of equation 3x^2 +mx+2=0,find the value of m
Answers
Answered by
8
Step-by-step explanation:
3x^2 +mx+2=0
3(√2/√3)^2 + m(√2/√3)+2=0
3(2/3) + m(√2/√3)+2=0
m(√2/√3)= -4
m= -4(√3/√2)
= -2√2*√3
= -2√6
Similar questions