Question

If √2\3 is a solution of equation 3x^2 + mx +2=0, find the value of m

Answer 1

Step-by-step explanation:

root : √2/3

p(x)= 3x²+mx+2=0

putting the value of x as √2/3

           we get ,

3(√2/3)²+m(√2/3)+2=0

⇒3(2/9)+m(2/9)+2=0

⇒m(2/9)=-2-2/9

⇒m=-20/9 (9/2)

⇒m=-10

     hope it helps