if √2/3 is a solution of equation 3x^2+mx+2=0, find the value of m
Bhasksr:
what is the answer to this question?
I hav done it but im not sure
Answers
Answered by
201
Answer:
If the question means to say √2/3 is a root, then m = -4√2.
If the question means to say √(2/3) is a root, then m = -2√6.
Step-by-step explanation:
It is unclear in the question if √2/3 or √(2/3) is meant to be the solution. Let's do both...
Case 1
√2/3 is a solution of 3x² + mx + 2 = 0
=> 3×(√2/3)² + m×(√2/3) + 2 = 0
=> 2/3 + m×(√2/3) + 6/3 = 0
=> m×(√2/3) + 8/3 = 0
=> m×√2 + 8 = 0
=> m×√2 = -8
=> m = -8 / √2 = -8√2 / 2 = -4√2
Case 2
√(2/3) is a solution of 3x² + mx + 2 = 0
=> 3×√(2/3)² + m×√(2/3) + 2 = 0
=> 2 + m×√(2/3) + 2 = 0
=> m×√(2/3) = -4
=> m = -4√3 / √2 = -4√6 / 2 = -2√6
thanks but it is wrong :D
3*(root2/3)^2 + (-4root2)*(root2/3) + 2 = 0.... checked just now in computer. Answer is CORRECT for (root2)/3 to be a root.
Perhaps the question was meant to say that root(2/3) is a root? If that's the case, then same method and you get m = -2root6.
Perhaps the question was meant to say that root(2/3) is a root? If that's the case, then same method and you get m = -2root6.
Editted answer to include both possible interpretations of your question. Before saving, I have checked both in a computer and they are definitely correct.
Answered by
56
this is a clear explanation.. hope this helps you
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