If 2/3 is a solution of the equation 7x square + kx - 3=0 find the value of k
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Answered by
0
p(2/3) = 7(2/3)² + k(2/3) - 3 = 0
= 7(4/9) + 2k/3 - 3 = 0
= 28/9 + 6k/9 -9/9 = 0
= (6k + 19) / 9 = 0
= 6k = - 19
k = - 19 / 6
Answered by
5
Answer:
-1/6
Step-by-step explanation:
7x²+kx-3=0
=>7(2/3)²+k(2/3)-3=0
=>7×4/9+k(2/3)-3=0
=>28/9+k(2/3)=3
=>k(2/3)=3-28/9= -1/9
=>k=(-1/9)×(3/2)= -1/6
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