if 2/3,k,5k/8 are in A.P.,find the value of k.
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Answered by
21
given 2/3, k,5k/8 are in AP
if a,b,c are in ap
2b= (a+c)
2k = 2/3+5k/8
2k-5k/8 = 2/3
(16k-5k)/8=2/3
11k/8 = 2/3
k= 2/3*8/11
k= 16/33
if a,b,c are in ap
2b= (a+c)
2k = 2/3+5k/8
2k-5k/8 = 2/3
(16k-5k)/8=2/3
11k/8 = 2/3
k= 2/3*8/11
k= 16/33
Answered by
13
Given 2/3,k,5k/8 are in AP
Let a1 = 2/3
a2 = k
a3 = 5k/3
We know that when numbers are in AP their common difference is same
So, a2 - a1 = d
= k- 2/3 = d
Also a3 - a2 = d
5k/3 - k = d
Therefore k- 2/3 = 5k/3 - k
(3k - 2)/3 = (5k - 3k)/3
3k - 2 = 2k
k = 2
Let a1 = 2/3
a2 = k
a3 = 5k/3
We know that when numbers are in AP their common difference is same
So, a2 - a1 = d
= k- 2/3 = d
Also a3 - a2 = d
5k/3 - k = d
Therefore k- 2/3 = 5k/3 - k
(3k - 2)/3 = (5k - 3k)/3
3k - 2 = 2k
k = 2
Nikti:
I am very very sorry please delete my answer I used 5k / 3 in place of 5k/8
Procedure is same u just change the value by 8
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