. If 2/3, k, 5k/8 are in A.P then the value of k is *
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If 2/3, k, 5k/8 are in A.P then there is a common different between then let the common difference 'd'
ie K+d = 5k/8
=> d= -3k/8
ie (2/3)+d=k
=> (2/3)+(3k+8)=k
(16-9k) / 24=k
16-9k=24k
24k+9k=16
33k=16
k=16/33
there for the value of k is 16/33
The series is 2,3,16,33,10,33
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