if 2/3 of the men are married to 3/7 of the women and the total population is more than 1000. if all marriges happen within town then find the smallest possible no. of total population
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Answered by
41
Answer:
1012
Step-by-step explanation:
Let say Man = M
& Woman = W
2/3 Of Man = 3/7 of Woman
=> 2M/3 = 3W/7
=> 14M = 9W
=> W = 14M/9
Total Population = M + W
= M + 14M/9
= (9M + 14M)/9
= 23M/9
for every 9 Man there are total 23 population
for 9x man there is 23 x population ( man has to be 9x as woman are 14M/9 so woman will be 14x )
23 x > 1000
=> x > 1000/23
=> x > 43.47
=> x = 44 ( to have smallest possible number of total population)
Man = 9 * 44 = 396
Woman = 14 * 44 = 616
Total Population = 1012
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