History, asked by prabhadarling, 11 months ago

If (2.3)^x = (0.23)^y = 1000 then find the value of 1/x-1/y.

Answers

Answered by sahookadambini234
3

Answer:

1/3

Explanation:

x=log (2.3)1000

=>1/x=log (1000)2.3

y=log (0.23)1000

=>1/y=log (1000)0.23

1/x-1/y=log (1000)2.3-log (1000)0.23

=1/3 (ans ).

Answered by mpssankar
5

Answer:

hope this helps you :)

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