Question

If (2.3) x = (0.23) y = 1000 then find the value of 1\x+1\y

Answer 1

Answer:

bichi paka, gudhi marani

Answer 2

Step-by-step explanation:

(2.3)^x=1000 and (0.23)^y=1000

log(2.3)^x =log1000 and log(0.23)^y=1000

xlog(2.3)=log10^3 and log(0.23)^y =log10^3

xlog(2.3) = 3log10 and ylog(0.23) =3log10

xlog(2.3) = 3×1 and ylog(0.23)=3 [log10=1]

⇒log(2.3)=3/x and log0.23 =3/y

/////////////

3/x -3/y =log2.3 -log(0.23)

3(1/x - 1/y) =log(2.3/0.23)

⇒1/x - 1/y ={log(10)}/3

⇒1/x-1/y =(1)/3

⇒1/x -1/y =1/3