if (2.3) ^x=(0.23) ^y=1000, then find the value of 1/x-1/y
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1
Answer:
1/3
Step-by-step explanation:
(2.3)x=1000
add log
3
(2.3) x=log10
3
x=3log. 10
2.3
x/3=log 10
2.3
(0.23)y=1000
3
(0.23)y=log10
y=3log10
0.23
y/3=log10
0.23
3/x=log2.3
10
3/y= log0.23
10
3/x-3/y=log2.3-log0.23
10. 10
log10( 23/10)/(23/100)
10
log10
3/x-3/y=1
3(1/x-1/y)=1
1/x-1/y= 1/3
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