Math, asked by arunajagarapu1986, 16 days ago

if (2.3) ^x=(0.23) ^y=1000, then find the value of 1/x-1/y​

Answers

Answered by shanmukhasaisri5627
1

Answer:

1/3

Step-by-step explanation:

(2.3)x=1000

add log

3

(2.3) x=log10

3

x=3log. 10

2.3

x/3=log 10

2.3

(0.23)y=1000

3

(0.23)y=log10

y=3log10

0.23

y/3=log10

0.23

3/x=log2.3

10

3/y= log0.23

10

3/x-3/y=log2.3-log0.23

10. 10

log10( 23/10)/(23/100)

10

log10

3/x-3/y=1

3(1/x-1/y)=1

1/x-1/y= 1/3

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