If (2.3)^x=(0.23)^y=1000, then find the value of 1/x-1/y please..
Answers
Answered by
1
Answer:
1/3
Step-by-step explanation:
Apply logarithms:
2.3^x = 0.23^y = 1000
x Log 2.3 = y Log 0.23 = Log 1000
x Log 2.3 = y (Log 2.3/10 ) = 3
x Log 2.3 = y (Log 2.3 - Log 10) = 3
1/x = (Log 2.3)/3
1/y = (Log 2.3 -1)/3 = (Log 2.3)/3 - 1/3
1/y = 1/x - 1/3
Answered by
1
Step-by-step explanation:
in the the answer is clear
Attachments:
Similar questions