Math, asked by krishnavamshir99, 8 months ago

If (2.3)^x=(0.23)^y=1000, then find the value of 1/x-1/y please..​

Answers

Answered by frarhlote
1

Answer:

1/3

Step-by-step explanation:

Apply logarithms:

2.3^x = 0.23^y  = 1000

x Log 2.3 = y Log 0.23 =  Log 1000

 x Log 2.3  = y  (Log 2.3/10 ) = 3

x Log 2.3   = y (Log 2.3 - Log 10) = 3

1/x = (Log 2.3)/3  

1/y = (Log 2.3 -1)/3 = (Log 2.3)/3  - 1/3

1/y = 1/x - 1/3

Answered by vamsi1022
1

Step-by-step explanation:

in the the answer is clear

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