If (2.3)x=(0.23)y=1000then find the value of 1/x-1/y
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Now consider the log in both side of the equation, log(2.3) ^{x} = log(10) ^{3 . And 1/x = log(2.3)/3. Now, (0.23)^{y} =10^{3} now we find yaccording to ...
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