Chemistry, asked by sc11, 19 days ago

If 2.30 g of N2 gas has a volume of 0.40 L and a pressure of 5.1 atm , what is its Kelvin temperature?

Answers

Answered by yashingale515

0

Answer:

Assuming pressure is constant:

Explanation:

V1T1=V2T2 (T in Kelvin)

20oC=20+273=293K

150oC=150+273=423K

0.5293=V2423→V2=0.5×423293=0.72L

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