Question

If 2+3i in a root of x square+a x +b=0

Answer 1

Step-by-step explanation:

(2+root3i)^2+p*2+roit3 i)+q=0 4-3+4root3i+2p+root3pi+q=0

(1+2p+q)(4root3+root3p=0

2p + q = - 1

p = - 4

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