If 2^3n/8 +1 +3×2^n/2 +3×2^2n/4=4913 Then find the value of n
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It is given that,
sinθ=x and secθ=y
⇒ cosθ=
secθ
1
=
y
1
And, cotθ=
sinθ
cosθ
⇒ cotθ=
xy
1
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