If{2^(3x-1) +10}+7=6, then x=
(a) -2
(b) 2
(C) 1
(d) 0
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c) 1
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2^(3x-1)+10=7×6=42
=> 2^(3x-1) = 32
=> 2^(3x-1) = 2^5
As LHS IS HAVING SAME BASE AS THAT OF RHS therefore, we can now easily compare the powers
Therefore, => 3x-1 = 5
=> 3x = 6
=> X = 2
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