if (2^3x-1+10) divided 7=6 find the x value
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Answer:
(2^3x-1+10)/7=6
2^3x-1+10=42
2^3x-1=42-10
2^3x-1=32
we can also write 32 as 2^5
hence:
2^3x-1=2^5
take 2 as common
therefore:
3x-1=5
3x=6
therefore x=2
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