Question

if 2+4+6...+n/1+3+5+...+n=37/36 find the value of n? ​

Answer 1

Answer:

sum of n even natural numbers = n (n+1)

sum of n odd natural numbers = n^2

n (n+1)/n^2 = 37/36

n+1/n = 37/36

cross multiplication

36 (n+1) = 37n

36n+36 = 37n

37n-36n = 36

n = 36