if (2,4)is a solution of ksquare x -3y=4 find the value of k
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6
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Here's your answer...
If (2,4) is the solution of k²x - 3y = 4,
then x = 2 and y = 4.
Substituting these values in the given equation...
2k² - 3×4 = 4
2k² - 12 = 4
2k² = 16
k² = 8
k = + or - 2 root 2
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Here's your answer...
If (2,4) is the solution of k²x - 3y = 4,
then x = 2 and y = 4.
Substituting these values in the given equation...
2k² - 3×4 = 4
2k² - 12 = 4
2k² = 16
k² = 8
k = + or - 2 root 2
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Answered by
1
putting 2in place in of x and 4in place of y
2k^2-3×4=4
2k^2-12=4
2k^2=16
k^2=8
k=2root2
2k^2-3×4=4
2k^2-12=4
2k^2=16
k^2=8
k=2root2
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