Question

If(2,4) is the mid point of join of (6,a) and (b,5),Then value of a and b respectively is

Answer 1

ATQ

√16+a^2+16-8a=√b^2+4-4b+1 =2√(6-b) ^2+(a-5)^2(root is at whole!)

Distance formula seems Hard approach so we'll use section formula...

For x Value

$\frac{6 + b}{2} = 2$

$b = - 2$

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For y Value

$\frac{a + 5}{2} = 4$

$a = 3$

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