Question

If (-2, -4) is the midpoint of (6, -7) and (x, y), then the values of x and y are ​

Answer 1

Answer:

the vertices of a triangle are (1, 2) (P,

-3) and (-4, q), centrol be at the point (5,

-1), then find the values of p and q.

Step-by-step explanation:

Thanks

but sorry

Answer 2

The value of x and y are -10 and -1

Explanation:

Given:

1. (-2, -4) is the midpoint of (6, -7) and (x, y)

To find

The value of x and y

FORMULA

MIDPOINT:   $\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2} =(x,y)$

Solution:

==> Apply the given values in the midpoint formula

==>  (x₁,y₁)=(6,-7)

==> (x₂,y₂) =(x,y)

==> (x,y)=(-2,-4) ==> Mid point

we have to find the x and y values,

==> x₁=6

==> y₁=-7

==> x₂= x

==>y₂ = y

==> x =-2

==> y = -4

Equating x values

==>  $\frac{x_{1}+x_{2}}{2} =x$

==>   $\frac{6+x}{2} =-2$

==> 6+x = -2×2

==> 6+x =-4

==> x = -4-6

==> x= -10

Equating y values

==>    $\frac{y_{1}+y_{2}}{2} =y$

==>    $\frac{-7+y}{2} =-4$

==>  -7+y = -4×2

==>  -7+ y =-8

==>  y=-8+7

==> y=-1

The value of x and y are -10 and -1