Question

if 2,5 are zeroes of polynomial p(x), then find p(x)​

Answer 1

Answer: hey mate here is your answer

Step-by-step explanation: let p(x)=$ax^{2} + bx +c$ ...1

sum of zeroes = $\frac{-\\b}{a}$ =$\alpha +\beta$

=2+5 = 7

product of  zeroes = $\frac{c}{a} = \alpha \beta$

2 X  5  = 10

now putting values in equation 1

therefore the required polynomial is  $x^{2} + 7x + 10$

hope this may help you

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