Question

if (-2,5) is the centre of the circle which touches
y-axis, then the equation of the circle is​

Answer 1

Answer:

x^2 + y^2 + 4x − 10y + 25 = 0

Step-by-step explanation:

If the circle touches Y- axis , then its x- coordinate has magnitude equal to radius (r).

∴ centre of circle is (−2,5).

then , r = 2

∴ equation of circle is :

(x+2)^2 + (y−5)^2 = 4

⇒x^2 + y^2 + 4x − 10y + 25 = 0

Hence, the required answer =

x^2 + y^2 + 4x − 10y + 25 = 0

Answer 2

Answer:

If the circle touches Y- axis , then its x- coordinate has magnitude equal to radius (r).

∴  centre of circle is (−2,5).

then ,  r=2

∴  equation  of  circle  is

(x+2)2+(y−5)2=4

⇒x2+y2+4x−10y+25=0

Step-by-step explanation:

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