if (2,5) is the solution of 2x+3y =m. find the value of m
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since this point is solution of the given line
....hence, point will satisfy the eqn
put X!=2,y=5..in 2x+3y-m=0
2(2)+3(5)-m=0
m=19
....hence, point will satisfy the eqn
put X!=2,y=5..in 2x+3y-m=0
2(2)+3(5)-m=0
m=19
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