if 2/5 of a number exceeds 1/7 of the same number by 36 find the number
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let the number be X.
A / q ,
➡️ 2x / 5 - X / 7 = 36
➡️ 14x - 5x / 7 = 36
➡️ 9 x. = 36 × 7
➡️ X = 28 Ans
A / q ,
➡️ 2x / 5 - X / 7 = 36
➡️ 14x - 5x / 7 = 36
➡️ 9 x. = 36 × 7
➡️ X = 28 Ans
john332:
let the number be x
Let the reqired number be x
now2/5 of x=2x/5
x exceeds 1/7 of number 36
there for the equation 2x/5=x/7+36
2x/5-x/7-36=0
9(x-140)/35=0
x=140
now2/5 of x=2x/5
x exceeds 1/7 of number 36
there for the equation 2x/5=x/7+36
2x/5-x/7-36=0
9(x-140)/35=0
x=140
plz can u write it as clear
here
let number be 'x'
then
2/5*x=2x/5
according to question
x exceeds 1/7 of number 36
so 2x/5=x/7+36
or,2x/5-x/7=36
or,(14x-5x)/35=36
or,9x=35*36
or,9x=1260
x=140
let number be 'x'
then
2/5*x=2x/5
according to question
x exceeds 1/7 of number 36
so 2x/5=x/7+36
or,2x/5-x/7=36
or,(14x-5x)/35=36
or,9x=35*36
or,9x=1260
x=140
u are wrong princess
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